Positivity of GCD tensors and their determinants

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Positivity of GCD tensors and their determinants

Positivity of GCD tensors and their determinants

Year : 2025

Publisher : Elsevier

Source Title : Linear Algebra and its Applications

Document Type :

Abstract

Let $S=left{s_1, s_2, ldots, s_nright}$ be an ordered set of $n$ distinct positive integers. The $m$ thorder $n$-dimensional tensor $mathscr{T}_{[S]}=left(t_{i_1 i_2 ldots i_m}right)$, where $t_{i_1 i_2 ldots i_m}=operatorname{GCD}left(s_{i_1}, s_{i_2}, ldots, s_{i_m}right)$, the greatest common divisor (GCD) of $s_{i_1}, s_{i_2}, ldots$, and $s_{i_m}$ is called the GCD tensor on $S$. The earliest result on GCD tensors goes back to Smith [Proc. Lond. Math. Soc., 1976], who computed the determinant of GCD matrix on $S={1,2, ldots, n}$ using the Euler’s totient function, followed by Beslin-Ligh [Linear Algebra Appl., 1989] who showed all GCD matrices are positive definite. In this note, we study the positivity of higher-order tensors in the $k$-mode product. We show that all GCD tensors are strongly completely positive (CP). We then show that GCD tensors are infinite divisible. In fact, we prove that for every positive real number $r$, the tensor $mathscr{T}_{[S]}^{o r}=left(t_{i_1 i_2, ldots i_m}^rright)$ is strongly CP. Finally, we obtain an interesting decomposition of GCD tensors using Euler’s totient function $Phi$. Using this decomposition, we show that the determinant (also called hyperdeterminant) of the $m$ th-order GCD tensor $mathscr{T}_{[S]}$ on a factor-closed set $S=left{s_1, ldots, s_nright} text { is } prod_{i=1}^n Phileft(s_iright)^{(m-1)^{(n-1)}} .$